Question

find the value k if x = 1,y=6 is a solution of the equation 8x-ky+k^2=0​

Answer 1

Answer:

k=2,4

Step-by-step explanation:

8x-ky+k²=0

8(1)-k(6)+k²=0

8-6k+k²=0

k²-6k+8=0

k²-2k-4k+8=0

k(k-2)-4(k-2)=0

(k-2)(k-4)=0

k-2=0 or k-4=0

k=0+2 or k=0+4

k=2 or k=4

Answer 2

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