Question

find the value k if x=1, y=6 is a solution of the equation 8x-ky+k^2=0
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Answer 1

Answer:

x=1 y=6

8x-ky+k²=0

8(1)-k(6)+k²=0

k²-6k+8=0

k²-2k-4k+8=0

k(k-2)-4(k-2)=0

(k-4)(k-2)=0

Therefore k=4,2