Question

Find the value k if y+3 is the factor of 3y2 - ky + 6

Answer 1

Answer:

Hii

Here is ur answer ⬇️

y+3=0

y=-3

3y2-ky+6=0

=3(-3)(2)-k(-3)+6

=-18+3k+6

=-12+3k

12=3k

12/3=k

k=4

Hope it helps u!

Answer 2

Solution :

If y+3 is a factor of the given polynomial 3y² - ky + 6 = 0

→ y + 3 = 0

→ y = -3

Now , substitute the value of y in the given polynomial,

→ 3y² - ky + 6

→ 3(-3)² - (-3)k + 6 = 0

We equate the equation to zero, because the substitution of the factor always gives the value 0.

When solving the equation ,

→ 27 + 3k + 6 = 0

→ 3k = 33

→ K = 33/3

→ K = 11