Question

Find the value k so that the area of the triangle with vertices (1,-1) , (-4, 2k) and (-k,-1) is 24 sqaure units

Answer 1

area of triangle= 1/2(1×(2k+1)-4(-1-1)-k(1+4))
1/2(2k+1+8-5k)
1/2(9-3k)=24
9-3k=24
k=15/3
k=5