Question

Find the value k, such that the following quadratic equation has equal roots
(k - 12)x^2- 2(k - 12)x + 2 = 0.

Answer 1

Step-by-step explanation:

(k−12)(x2)−2(k−12)x+2=0

Step 1: Add 12x^2 to both sides.

kx2−2kx−12x2+24x+2+12x2=0+12x2

kx2−2kx+24x+2=12x2

Step 2: Add -24x to both sides.

kx2−2kx+24x+2+−24x=12x2+−24x

kx2−2kx+2=12x2−24x

Step 3: Add -2 to both sides.

kx2−2kx+2+−2=12x2−24x+−2

kx2−2kx=12x2−24x−2

Step 4: Factor out variable k.

k(x2−2x)=12x2−24x−2

Step 5: Divide both sides by x^2-2x.

k(x2−2x)

x2−2x

=

12x2−24x−2

x2−2x

k=

12x2−24x−2

x2−2x

Answer:

k=

12x2−24x−2

x2−2x

Answer 2

Step-by-step explanation:

Find the value k, such that the following quadratic equation has equal roots

(k - 12)x^2- 2(k - 12)x + 2 = 0.