Question

find the value log 81 base 9​

Answer 1

Answer:

log81= log9^2 = 2log9 [°•° loga^n = nloga]

Therefore log81 to the base 9= log81/log9 [ °•°logb to the base a= logb/loga]

=2log9/log9

=2

Thus the answer is 2

#answerwithquality

#BAL

PLEASE MARK MY ANSWER AS THE BRAINLIEST PLSSS

Answer 2

Answer:

The value log 81 base 9​ is 2.

Step-by-step explanation:

As per the question,

We need to find the the value $log_{9}81$

As we know,

$=log_{9} 81\\\\=log_{9} 9^{2} \\\\=2log_{9} 9\\\\=2$(By applying the property of log :  $log_{n}n=1$ )

Hence,

The value log 81 base 9​ is 2.

#SPJ3