Question

find the value of 0.0275 * (9.207)^2 with the help of log

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Answer 1

Step-by-step explanation:

Given:

$0.0275 \times ( {9.207)}^{2}$

To find: Find the value using log.

Solution:

Let

$x = 0.0275 \times ( {9.207)}^{2}$

Take log both sides

$log(x) = log(0.0275 \times ( {9.207)}^{2})$

Apply log properties

$\bold{log(ab) = log(a) + log(b) } \\ \bold{log( {a}^{n} ) = n log(a) }$

$log(x) = log(0.0275) + log ( {9.207)}^{2}\\ \\ log(x) = log(0.0275) + 2 log(9.207)$

find value of log(0.0275) and log(9.207) from log table

$log(x) = -1.56+2\times 0.96\\ \\ log(x) = -1.56+1.93 \\ \\log(x)=0.37$

Take antilog to find the value of x

$x = {10}^{0.37} \\\\x=2.34$

Final answer:

$\bold{\red{0.0275 \times ( {9.207)}^{2}=2.34}}$

Hope it helps you.

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