Find the value of 0 (0º < 0 < 90°) if :
(i) cos 63° sec (90° – ) = 1
(ii) tan 35° cot (90° - 0) = 1.
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Step-by-step explanation:
i) For the first equation we can take the value of O as 27°
Because,
cos 63° × sec (90°-27°) = 1
sin 27° × cosec 27° = 1
sin 27° × 1/sin 27° = 1
So, 1 = 1
We can write cos 63° as sin 27° as it is complementary.And we can write
cot(90°-27°) as cosec27° which can also be written as 1/sin27°.
ii) For the second equation we can take the value of O as 55°
Because,
tan 35° × cot (90° - 55°) = 1
tan35° × cot 35° = 1
tan35° × 1/tan35° = 1
So, 1 = 1
Here we r not taking anything as complementary
Instead taking 90° - 55° as 35° only so that we can equate both.
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