Question

Find the value of 0 if equation
Coso x² – 2 sinox-coso -0 has real roots​

Answer 1

Answer:

Apply the formula:-(a+b)(a-b)=a^2-b^2

{{3x+2y)(3x-2y)(9x^2+4y^2)} = (9x^2-4y^2)(9x^2+4y^2)

(Again apply the formula above) =81x^4-16y^4

This will be the answer.