Math, asked by pramilapradhan2137, 7 hours ago

Find the value of, 1^0+2^0+...+69^0
a. 1
b.0
c.69
d. 169​

Answers

Answered by XXItsKaminiBandiXX
3

answer

69

Step-by-step explanation:

Answer

81265×169−81265×69

=81265×(169−69)

=81265×100

=8126500.

Answered by chaturvedidevansh474
0

Answer:

69

Step-by-step explanation:

1^0+2^0+...+69^0

=1+1+1+...+1 (69 times)

=69

Hope, you understood.

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