Find the value of, 1^0+2^0+...+69^0
a. 1
b.0
c.69
d. 169
Answers
Answered by
3
answer
69
Step-by-step explanation:
Answer
81265×169−81265×69
=81265×(169−69)
=81265×100
=8126500.
Answered by
0
Answer:
69
Step-by-step explanation:
1^0+2^0+...+69^0
=1+1+1+...+1 (69 times)
=69
Hope, you understood.
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