Find the value of (1.04)² using suitable identity
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3
(101)
2
=(100+1)
2
Using (a+b)
2
=a
2
+b
2
+2ab
(100+1)
2
=100
2
+1
2
+2×100×1
=10000+1+200
=10000+201
=10201.
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