Question

FIND the value of (-1)+(-1)^2n+(-1)^2n+1+(-1)^4n+1 where n is any positive intejer

Answer 1

Step-by-step explanation:

(-1)+(-1)^2n+(-1)^2n+1+(-1)^4n+1

if n is an even positive integers:-

= ( -1)+1-1-1.

[ because (-1)^n=1 ( even positive

integers)]

=. -2. Ans.

if n is an odd positive integers:-

(-1)+(-1)^2n+(-1)^2n+1+(-1)^4n+1

=. -1+1-1-1=-2

[because (-1)^n =-1 (0dd positive integers)]

[{(-1)^2n= if i let n=1 so

(-1)^2×1= (-1)^2=1}

{ (-1)^2n= if i let n=3 so

(-1)^2×3= (-1)^6=1............

.....................(-1)^2n=1}]