Question

Find the value of: (-1) + (-1)2n +(-l) 2n+1 + (-l)4n+1 , where n is any positive odd integer.​

Answer 1

Answer:

Reason is :  

n is a positive odd integer. So (-1)^n = -1

2n is a positive EVEN integer

.[(-1)^2]^n = 1^n = 1

2n+1 is a positive ODD integer  

(-1)^{2n+1}=[(-1)^2]^n* * (-1)^1}= 1^{n} (-1)=-1\\  

4n+2 is always a positive even integer.

(-1)^{4n+2}=[(-1)^2]^{2n+1}= 1^{2n+1}=1\\