find the value of [(1\11)^0+(3\10)^0]^0÷7^1
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Answered by
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Step-by-step explanation:
(1\11)^0 = 1/11
(3\10)^0]^0 = 3/10^0×0 = 3/10
7^1 =
1 + 3 ÷ 7. This can be written as 1. +. 3. × 1
--- --- ---- ---- ----
11. 10. 11. 10. 7
(because 7 = 7/1, to change division to multiplication we have to reciprocal...
Hence 7/1 = 1/7....
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2
Answer:
find the value of [(1\11)^0+(3\10)^0]^0÷7^1
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