Question

find the value of 1/125^-(2/3)+ 1/625^-(3/4) + 1/729^(3/6)
plzz tell me ans
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Answer 1

Concept Introduction:

The numerator and the denominator of a fraction is generally are natural numbers.

Given Information:

The equation is given $\frac{1}{125} ^-\frac{2}{3} +\frac{1}{625}^-\frac{3}{4} +\frac{1}{729} ^\frac{3}{6}$

To find:

The simplified answer of the equation.

Solution:

According to the problem,

$\frac{1}{125} ^-\frac{2}{3} +\frac{1}{625}^-\frac{3}{4} +\frac{1}{729} ^\frac{3}{6}$

$=\frac{1}{5^2} ^-\frac{2}{3} +\frac{1}{5^4} ^-\frac{3}{4} +\frac{1}{3^6} ^\frac{3}{6}$

$(\frac{1}{5})^-2+ (\frac{1}{5})^-3+(\frac{1}{3} )^3$

$=25+125+\frac{1}{27}$

$=150+\frac{1}{27}$

$=150$

Final Answer:

The answer is $150$