Question

find the value of (1/2)-¹+(1/3)-²+1/4-³​

Answer 1

$\sf\huge\bold{Answer:}$

Given :

$( \frac{1}{2} ) {}^{ - 1} + ( \frac{1}{3} ) {}^{ - 2} + (\frac{1}{4} ) {}^{ - 3}$

Solution :

$( \frac{1}{2} ) {}^{ - 1} + ( \frac{1}{3} ) {}^{ - 2} + (\frac{1}{4} ) {}^{ - 3}$

Using identity

$⇒{a}^{m} = \frac{1}{ {a}^{ - m} }$

we get,

${2}^{1} + {3}^{2} + {4}^{3}$

Now,

$⇒{a}^{m} = a \times a \times a \times ...m \: times.$

For example

⇒4²=4×4 (i.e two times 4) =16

so,the term will become

$= 2 + (3 \times 3) + (4 \times 4 \times 4) \\ = 2 + 9 + 64 \\ = 75$

So,your solution for the term$( \frac{1}{2} ) {}^{ - 1} + ( \frac{1}{3} ) {}^{ - 2} + (\frac{1}{4} ) {}^{ - 3}$ after step by step explanation is 75.

Answer 2

Answer:

Hopes it will help you dear

.xD