Question

find the value of (1+√2)(1-√2)​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

we know that (a+b) (a-b)

$= > {a}^{2} - {b}^{2}$

here a = 1

and b =√2

therefore,(a^2)-(b^2)

$= {1}^{2} - { \sqrt{2} }^{2} \\ = 1 - 2 \\ = - 2$

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