Question

Find the value of 1+√2÷1-√2​

Answer 1

Answer:

I don't know

Step-by-step explanation:

any other questions

Answer 2

Answer:

Given : \sqrt{2}=1.414

2

=1.414

To Find :\frac{1}{\sqrt{2}+1}

2

+1

1

Solution :

\frac{1}{\sqrt{2}+1}

2

+1

1

Rationalize

\frac{1}{\sqrt{2}+1} \times \frac{\sqrt{2}-1}{\sqrt{2}-1}

2

+1

1

×

2

−1

2

−1

Identity : (a+b)(a-b)a^2-b^2(a+b)(a−b)a

2

−b

2

\frac{\sqrt{2}-1}{2-1}

2−1

2

−1

\frac{\sqrt{2}-1}{1}

1

2

−1

1.414-11.414−1

0.4140.414

Hence \frac{1}{\sqrt{2}+1}=0.414

2

+1

1

=0.414

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