find the value of 1+2+3+..........+105
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Answer:
a=1
d=1
an=105
an=a+(n-1)d
105=1+(n-1)1
105=1+1n-1
n=105
Sn=n/2(2a+(n-1)d)
=105/2(2+(104*1)
=105/2(106)
=105*53
=5565
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