Math, asked by jyotibatra19, 1 year ago

Find the value of 1+2+3.....120?
a. 21255
b. 22155
c. 22515
d. 22255

Answers

Answered by Shubhangi4
2
Heya!!!

1+2+3.....120

It is an AP
As, common difference is same

Sum of all terns of AP=
 \frac{n}{2} \times (a + an)

n= number of terms
a= first term
an= last term

Firstly, we'll find n.

an = a + (n-1)d
120 = 1+ (n-1)1
119= n-1
n= 120

Sum =
 \frac{120}{2} \times (1 + 120)
= 60(121)
= 7260

jyotibatra19: i have given the options below and your answer doesnt match any of my answer
Shubhangi4: may be options are wrong
jyotibatra19: this question come in govt exam so i dnt thnk so
Shubhangi4: oh
Shubhangi4: ok
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