Question

find the value of (1 + 2 omega​

Answer 1

The value of the expression

The value of the expression 1.(2−ω).(2−

The value of the expression 1.(2−ω).(2−ω

The value of the expression 1.(2−ω).(2−ω2

The value of the expression 1.(2−ω).(2−ω2)+2.(3−ω)(3−

The value of the expression 1.(2−ω).(2−ω2)+2.(3−ω)(3−ω

The value of the expression 1.(2−ω).(2−ω2)+2.(3−ω)(3−ω2

The value of the expression 1.(2−ω).(2−ω2)+2.(3−ω)(3−ω2)+.+(n−1)(n−ω)(n−

The value of the expression 1.(2−ω).(2−ω2)+2.(3−ω)(3−ω2)+.+(n−1)(n−ω)(n−ω

The value of the expression 1.(2−ω).(2−ω2)+2.(3−ω)(3−ω2)+.+(n−1)(n−ω)(n−ω2

The value of the expression 1.(2−ω).(2−ω2)+2.(3−ω)(3−ω2)+.+(n−1)(n−ω)(n−ω2),

The value of the expression 1.(2−ω).(2−ω2)+2.(3−ω)(3−ω2)+.+(n−1)(n−ω)(n−ω2),1.(2-ω).(2-ω2)+2.(3-ω)(3-ω2)+.+(n-1)(n-ω)(n-ω2),

The value of the expression 1.(2−ω).(2−ω2)+2.(3−ω)(3−ω2)+.+(n−1)(n−ω)(n−ω2),1.(2-ω).(2-ω2)+2.(3-ω)(3-ω2)+.+(n-1)(n-ω)(n-ω2), where omega is an imaginary cube root of unity, is…….

The value of the expression 1.(2−ω).(2−ω2)+2.(3−ω)(3−ω2)+.+(n−1)(n−ω)(n−ω2),1.(2-ω).(2-ω2)+2.(3-ω)(3-ω2)+.+(n-1)(n-ω)(n-ω2), where omega is an imaginary cube root of unity, is…….pls mark me as brain list and follow me too