Question

Find the value of 1/27^-1/3+1/625^-1/4

Answer 1

HEY DEAR USER !!

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HERE IS UR ANSWER ::

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Solution :- (1/27)^-1/3 + (1/625)^-1/4

= [ (1/3)^3 ] ^-1/3 + [ (1/5)^4 ]^-1/4

= (1/3)^-1 + (1/5)^-1

= (3)^1 + (5)^1

= 3 + 5

= 8

HOPE IT HELPS.....

Answer 2

Hey mate !!

Here's the answer !!

We know the rules of exponents. They are:

$a^{-1} = \frac{1}{a^{1}}$

So, 

$\frac{1}{27}^{ \frac{-1}{3}} = 27^{\frac{1}{3}$

We know that, $27^{\frac{1}{3} = (3^{3})^{\frac{1}{3} = 3$

Similarly,

[tex]\frac{1}{625}^{\frac{-1}{4 }} = 625^{\frac{1}{4} = (5^{\frac{1}{4})^{4}} = 5 [/tex]

So we get 3 + 5 = 8

Hence the answer is 8

Hope my answer helps !!

Cheers !!