Question

Find the value of (1^3+1)/1+1 + (2^3 +1)/2+1 ...... (25^3 +1)/25+1​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

solved

Step-by-step explanation:

( y³+1)/(y+1) = y²-y+1

S =  (1^3+1)/(1+1) + (2^3 +1)/(2+1 )...... (25^3 +1)/(25+1​)

= ∑n² - ∑n + ∑1

= n(n+1)(2n+1)/6 - n(n+1)/2 + n

= n(n²+2)/3

= 25(627)/3

=25(209)

= 5045