Question

find the value of 1 / ✓3 + ✓2​

Answer 1

✓6= 2.45 is the correct answer

Plz Mark Me as A Brainlist

Answer 2

$\huge\bold{\gray{\sf{Answer:}}}$

$\bold{Explanation:}$

$\sf= > \dfrac{1}{ \sqrt{3} + \sqrt{2} }$

Here,we see that root values is in the denominator so ,in order to remove roots values from the denominator we use rationalising method.It is a method used when there are root values in the denominator.We can shift root towards numerator side and make denominator a simple.

Step1 : First step is to multiply both numerator and denominator with the opposite operational sign of denominator.

Step 2: After multiplication there is always an identity used in the denominator through which we remove root values.

Now ,let's solving questions:-

$\sf = > \dfrac{1}{ \sqrt{3} + \sqrt{2} } \times \dfrac{ \sqrt{3 } - \sqrt{2} }{ \sqrt{3} - \sqrt{2} }$

here ,this identity is used :-

$\bold{\boxed{(x + y)(x - y) = {x}^{2} - {y}^{2}}}$

$\sf= > \dfrac{ \sqrt{3} - \sqrt{2} }{ {( \sqrt{3}) }^{2} - {( \sqrt{2} )}^{2} } = \dfrac{ \sqrt{3} - \sqrt{2} }{3 - 2}$

$\sf= \sqrt{3} - \sqrt{2}$(answer)