Question

find the value of 1/[(3^4)^1/2]-2 ​

Answer 1

Answer:

this will help you in Pythagoras theorem

that is

h square is equal to p square plus b square

Answer 2

Answer: 1/[(3^4)^1/2]-2 =1/[(81)^1/2]-2

1/[(9)^2]^1/2]-2 = Here, the power of 9 and whole's power will cancel out .Then it will become...........

1/[(9)^1]-2 = 1/(9-2)

1/7..............................

Hence, 1/7 is the answer of this question...

Thanks.....