Math, asked by chopradhafrie, 1 year ago

FIND THE VALUE OF 1/3.cos36/sin54.sec16/cosec74

Answers

Answered by qais
3
(1/3)×(cos36°/sin54°)×(sec16°/cosec74°)

=(1/3)×[cos(90°-54°)/sin54°]×[sec(90°-74°)/cosec74°]

=(1/3)×(sin54°/sin54°)×(cosec74°/cosec74°)

=1/3
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