Math, asked by sankritisrivastava20, 1 year ago

Find the value of (1/3)power-1+(1/5)power-1-(1/6)power-1


EnnMushtaq: (3/1)+(5/1)–(6/1) =5+3–6=2
EnnMushtaq: the reciprocal of (1/3)^–1 is 3/1 and the power becomes positive.

Answers

Answered by rizwan35
7

( \frac{1}{3} )  {}^{ - 1}  + ( \frac{1}{5} ) {}^{ - 1}  - ( \frac{1}{6} ) {}^{ - 1}  \\  \\  = 3 + 5 - 6 \\  \\  = 8 - 6 \\  \\  = 2
hope it helps...
Similar questions