Question

find the value of [(1/4)-2_(1/3)-2÷(1/2)-3​

Answer 1

➤ Answer :-

$\dashrightarrow \sf \bigg( \frac{1}{4} \bigg) - 2 - \bigg( \frac{1}{3} \bigg) - 2 \div \bigg( \frac{1}{2} \bigg) - 3$

$\dashrightarrow \sf \frac{1}{4} - \frac{2}{1} - \frac{1}{3} - \frac{2}{1} \div \frac{1}{2} - \frac{3}{1}$

$\dashrightarrow \sf \frac{1 }{4} - \frac{2}{1} - \frac{1}{3} - \frac{2}{1} \times \frac{2}{1} - \frac{3}{1}$

$\dashrightarrow \sf \frac{1}{4} - \frac{2}{1} - \frac{1}{3} - \frac{4}{1} - \frac{3}{1}$

LCM of 4,1 and 3 is 12.

$\dashrightarrow \sf \frac{1 \times 3}{4 \times 3} - \frac{2 \times 12}{1 \times 12} - \frac{1 \times 4}{3 \times 4} - \frac{4 \times 12}{1 \times 12} - \frac{3 \times 12}{1 \times 12}$

$\dashrightarrow \sf \frac{3}{12} - \frac{24}{12} - \frac{4}{12} - \frac{48}{12} - \frac{36}{12}$

$\dashrightarrow \sf \frac{3 - 24 - 4 - 48 - 36}{12}$

$\dashrightarrow \sf \frac{( - 109)}{12}$

$\Huge\therefore$The answer is $\sf\frac{(-109)}{12}$