Question

Find the value of (1/4)^-2+(1/3)^-3+(1/2)^-4

Answer 1

(1/4)⁻² = 4² = 16

(1/3)⁻³ = 3³ = 27

(1/2)⁻⁴ = 2⁴ = 16

then

16+27+16 = 59

Answer 2

Answer:

59 is the required value of $(\frac{1}{4})^{-2} +( \frac{1}{3} )^{-3} + (\frac{1}{2} )^{-4}$.

Step-by-step explanation:

Explanation:

Given, $(\frac{1}{4})^{-2} +( \frac{1}{3} )^{-3} + (\frac{1}{2} )^{-4}$

As we know, the positive reciprocal of every negative exponent can be used to express it. A fraction with a reversed numerator and denominator is called a reciprocal.

Step 1:

From the question we have,

$(\frac{1}{4})^{-2} +( \frac{1}{3} )^{-3} + (\frac{1}{2} )^{-4}$

  $(4)^2 + (3)^3 + (2)^4$

⇒$16 + 27 + 16$

⇒ 59 .

Final answer:

Hence, the value of $(\frac{1}{4})^{-2} +( \frac{1}{3} )^{-3} + (\frac{1}{2} )^{-4}$ is 59.

#SPJ3