Math, asked by manishasamota85, 9 months ago

find the value of 1/4 x2 y2 z2 × (-6yz); where x =2 , y=3 and z=1.

Answers

Answered by 217him217

2

Answer:

1/4 * (x²y²z²)*(-6yz)

= 1/4 * (2²*3²*1²)*(-6*3*1)

=1/4 * (4*9)*(-18)

= 9*(-18)

=(-162)

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