Question

find the value of 1/ √8 -3√2​

Answer 1

$\mathfrak{\huge{\red{ANSWER}}}$

$\frac{1}{ \sqrt{8} - 3 \sqrt{2} } \\ \\ = \geqslant rationalising \: the \: denominator \\ \\ = \geqslant \frac{1}{ \sqrt{8} - 3 \sqrt{2} } \times \frac{ \sqrt{8} + 3 \sqrt{2} }{ \sqrt{8} + 3 \sqrt{2} } \\ \\ = \geqslant \frac{ \sqrt{8} + 3 \sqrt{2} }{( \sqrt{8} ) {}^{2} - (3 \sqrt{2}) {}^{2} } \\ \\ = \geqslant \frac{ \sqrt{8} + 3 \sqrt{2} }{8 - 18} \\ \\ = \geqslant \frac{ \sqrt{8} + 3 \sqrt{2} }{ - 10} \\ \\ = \geqslant \frac{ - ( \sqrt{8} + 3 \sqrt{2}) }{10} \\ \\ = \geqslant \frac{ - \sqrt{8} - 3 \sqrt{2} }{10}$

Answer 2

here's Ur answer

=(1/√8-3√2)×(√8+3√2/√8+3√2)

={√8+3√2}/{(√8)^2 - (3√2)^2}

={√8+3√2}/{8-9×2}

={√8+3√2}/{8-18}

={√8+3√2}/-10

={-√8-3√2}/10

hope It helps u

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