Question

find the value of 1/a².d²z/dx²+1/b².d²z/d²y when a²x²+b²y²-c²z²=0.​

Answer 1

Answer:

Given as x2/a2 + y2/b2 = 1 Differentiating the equation on both sides with respect to x, 2x/a2 + (2y/b2)(dy/dx) = 0 dy/dx = -xb2/ya2Read more on Sarthaks.com - https://www.sarthaks.com/627547/find-dy-dx-x-2-a-2-y-2-b-2-1

Step-by-step explanation:

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