find the value of 1/alpha -1/beta , if alpha+beta are the zeros of quadratic polynomial x^2+x-2
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Answered by
28
let us calculate, x^2 + x- 2 =0
so sum of roots a+ b= -1
product of roots ab = -2
so a- b = sqrt( a+b)^2 - 4ab ]
= sqrt[1+8]
= +_ 3
a+ b= -1-----------------------(I)
a- b = 3------------------------------(II)
so a= 1 & b = -2and if a+ b = -1
and a- b= -3
so a= -2 & b =1
soo1/a = 1 & 1/b = -1/2 OR 1/a= -1/2 & b= 1
so sum of roots a+ b= -1
product of roots ab = -2
so a- b = sqrt( a+b)^2 - 4ab ]
= sqrt[1+8]
= +_ 3
a+ b= -1-----------------------(I)
a- b = 3------------------------------(II)
so a= 1 & b = -2and if a+ b = -1
and a- b= -3
so a= -2 & b =1
soo1/a = 1 & 1/b = -1/2 OR 1/a= -1/2 & b= 1
Answered by
15
Answer:
1/alpha -1/ beta = -3/2...........
Step-by-step explanation:
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