Question

Find the value of 1-cosA/sinA by squaring both the numerator and denominator. Show the explanation with steps​

Answer 1

Step-by-step explanation:

1-cosA/sinA

(1-cosA)²/(sinA) ² (1)

using identity sin²A+cos²A=1

sin²A = 1-cos²A

sin²A = 1²-cos²A

we know that a²-b²=(a-b) (a+b)

1²-cos²A = (1-cosA) (1+cosA)

so sin²A = 1²-cos²A

sin²A= (1-cosA) (1+cosA)

from first equation

(1-cosA)²/(sinA)²

(1-cosA)²/(1-cosA) (1+cosA)

(1-cosA) /(1+cosA)