Find the value of (1 + cot 24° . cot 66 °) (1 − cot 18 ° . cot 72 °)
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In any right triangle
cot(90-@) = tan @
( 1+ cot 24°.cot (90- 24)° ) × ( 1- cot 18° . cot (90-18)°)
(1 + cot 24.tan 24) × (1 - cot 18.tan 18)
Since
cot @ . tan @ = 1
(1+1)×(1-1)
2×0
===>0
cot(90-@) = tan @
( 1+ cot 24°.cot (90- 24)° ) × ( 1- cot 18° . cot (90-18)°)
(1 + cot 24.tan 24) × (1 - cot 18.tan 18)
Since
cot @ . tan @ = 1
(1+1)×(1-1)
2×0
===>0
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