Question

Find the value of( 1 cube +2 cube 3 cube) to the power of -3/2

Answer 1

(1³+2³+3³)-³/²

(1+8+27)-³/²

(36)-³/²

6²×-³/²

6-³

1/6³

1/216

Answer 2

The correct answer is $\frac{1}{216}$.

Given: The term = $(1^{3} +2^{3} +3^{3} )^{\frac{-3}{2} }$.

To Find: The value of term

Solution:

$(1^{3} +2^{3} +3^{3} )^{\frac{-3}{2} }$

= $(1+8+27 )^{\frac{-3}{2} }$

= $(36 )^{\frac{-3}{2} }$

= $(6^{2} )^{\frac{-3}{2} }$

= $(6 )^{-3}$

= $(\frac{1}{6} )^{3}$

= $\frac{1}{216}$

Hence, the answer is $\frac{1}{216}$.

#SPJ2