Question

Find the value of (1-i)^1/3 by De Moivre's theorem.​

Answer 1

Answer:

Applied Mathematics 1. ∴ Add period 2k , x 3 = 2 [ cos ( 1 3 ) ( π 4 + 2 k π ) + i sin ( π 4 + 2 k π ) ] By applying De Moivres theorem, x = 2 2 [ cos ( 1 3 ) ( π 4 + 2 k π ) + i sin ( 1 3 ) ( π 4 + 2 k π ) ] where k =0,1,2. Roots are

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Answer 2

Answer:

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