find the value of (1+i)(1+i^2)(1+i^3)(1+i^4){1 marks question}
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3
the answer of this question is 0.
Anonymous:
nice ☺.
Answered by
2
(1+i )(1+i²)(1+i³)(1+i⁴)
let (1+i )(1+i³)(1+i⁴) = x
solving (1+i²)
= 1+(√-1)²
= 1-1
= 0
=> (1+i )(1+i²)(1+i³)(1+i⁴)
= (1+i )(1+i³)(1+i⁴)× (1+i²)
= x × 0
= 0
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