Math, asked by rangraashish1, 7 months ago

find the value of 1+i^14 +i^18+i^22​

Answers

Answered by saurabh2725
0

Answer:

=1 + i^14 + i^18 + i^22

=1 + (i²) ^7 + (i²)^9 + (i²)^11

=1+(-1) ^7 + (-1)^9+(-1)^11

=1-1-1-1

= -3

Step-by-step explanation:

(i²)= - 1

Answered by Anonymous
3

Always remember i² = -1

1 + i¹⁴ + i¹⁸ + i²²

= 1 + (i²)⁷ + (i²)⁹ + (i²)¹¹

= 1 + (-1)⁷ + (-1)⁹ + (-1)¹¹

= 1 + (-1) + (-1) + (-1)

= 1 - 1 - 1 - 1 = - 1 - 1 = - 2

The value of 1 + i¹⁴ + i¹⁸ + i²² = -2 .

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