Question

find the value of (1+i√3)^3?​

Answer 1

${(1 + \sqrt{3} i)}^{3} = 1 + 3 \times 1 \times \sqrt{3} i + 3 \times 1 \times 3 {i}^{2} + 3 \sqrt{3} {i}^{3} \\ \\ = > 1 + 3 \sqrt{3} i + 9 \times ( - 1) + 3 \sqrt{3} {i}^{2} .i \\ \\ = > 1 + 3 \sqrt{3} i - 9 + 3 \sqrt{3} \times ( - 1).i \\ \\ = > 1 - 9 + 3 \sqrt{3} i - 3 \sqrt{3} i = - 8$

So, the answer will be -8 ✔✔