Question

find the value of (-1)^n+(-1)^2n+(-1)^2n+1+(-1)^4n+2 where n is any positive and integer hand written​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

-1ⁿ + -1 ^(2n+1) + -1^(4n+2)

2n+1 is always an odd no. for all n is integer

so -1^(2n+1) = -1

4n+2 =2(2n+1) is always an even no.

so -1^(4n+2) =1

-1ⁿ + -1 + 1 = -1ⁿ

-1ⁿ = 1 for all n being even no. and

= -1 when n is odd no.