Question

Find the value of 1 power 3 + 2 power 3 + 3 power 2 + 8 square the whole power minus 5 by 2

Answer 1

We have to find the value of

$\quad (1^{3}+2^{3}+3^{2}+8^{2})^{-\frac{5}{2}}$

Step-by-step explanation:

Let us break the expression into parts first. This will help us solving the problem with ease.

• $1^{3}=1$
• $2^{3}=8$
• $3^{2}=9$
• $8^{2}=64$

Now, $1^{3}+2^{3}+3^{2}+8^{2}$

$=1+8+9+64$

$=82$

$\therefore (1^{3}+2^{3}+3^{2}+8^{2})^{-\frac{5}{2}}$

$=(82)^{-\frac{5}{2}}$

$=1.64\times 10^{-5}$ (approximately)

Answer:

$\quad (1^{3}+2^{3}+3^{2}+8^{2})^{-\frac{5}{2}}=1.64\times 10^{-5}$

Answer 2

Answer:

find the value of (1³+2³+3³)whole to the power of -3/2