Question

Find the value of 1/root 8-3 root 2.

Answer 1

$\frac{1}{\sqrt{8}}-3\sqrt2=\frac{1}{\sqrt{2\cdot4}}-3\sqrt2=\frac{1}{2\sqrt2}-3\sqrt2=\frac{\sqrt2}{2\sqrt2\sqrt2}-3\sqrt2=\\\\\frac{\sqrt2}{4}-3\sqrt2=(0.25-3)\sqrt2=-2.75\sqrt2=\frac{-11}{4}\sqrt2$

Answer 2

Answer:

-1/root2 is the answer