Question

find the value of 1/root18-root 32​

Answer 1

$\: \: \: \: \: \frac{1}{ \sqrt{18} - \sqrt{32} } \\ = \frac{1}{ \sqrt{18} - \sqrt{32} } \times \frac{ \sqrt{18} + \sqrt{32} }{ \sqrt{18} + \sqrt{32} } \\ = \frac{ \sqrt{18} + \sqrt{32} }{18 - 32} \\ = \frac{3 \sqrt{2} + 4 \sqrt{2} }{ - 14} \\ = \frac{7 \sqrt{2} }{ - 14} \\ = \frac{ \sqrt{2} }{ - 2 } \\ = - \frac{ \sqrt{2} }{ \sqrt{2} \times \sqrt{2} } \\ = - \frac{1}{ \sqrt{2} }$