Find the value of (1) sin(25π\3) (2) cos(41π\4).
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Answered by
25
( 1 ) Sin ( 25π / 3 )
=> Sin ( 8π + π /3 )
=> Sin π /3 [ Since Sin ( 2n π + ¢ ) = Sin ¢]
=> √3 / 2.
( 2 ) Cos ( 41 π / 4 )
=> Cos ( 10π + π /4 )
=> Cos π / 4 [ Since Cos ( 2nπ + ¢ ) = Cos ¢ ]
=> 1/√2.
=> Sin ( 8π + π /3 )
=> Sin π /3 [ Since Sin ( 2n π + ¢ ) = Sin ¢]
=> √3 / 2.
( 2 ) Cos ( 41 π / 4 )
=> Cos ( 10π + π /4 )
=> Cos π / 4 [ Since Cos ( 2nπ + ¢ ) = Cos ¢ ]
=> 1/√2.
Answered by
6
sin(25π/3) = sin(8π + π/3) = sinπ/3 = √3/2.
and , cos (41π/4 ) = cos (10π+π/4) = cosπ/4 = 1/√2.
and , cos (41π/4 ) = cos (10π+π/4) = cosπ/4 = 1/√2.
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