Question

find the value of
1.sin 31π/3
2.tan 3π/2
3.sec 25π/6
4.tan 6π
​

Answer 1

Answer:

1.

$\frac{ \sqrt{3} }{2}$

2.

$0$

3.

$\frac{\pi}{3}$

4.

$0$

Answer 2

Answer:

the value of

1.sin 31π/3=1

2.tan 3π/2=not define

3.sec 25π/6=2/$\sqrt{3}$

4.tan 6π=0

Step-by-step explanation:

sin 31π/3

=sin(10π+1/3π)

=sin(5×(2π)+1/3π)

=sin(1/3π)

=sin60°

=1

tan 3π/2

=tan(π+π/2)

=tan π/2

=not define

sec 25π/6

25π/6=2×(2π)+π/6

Each 2π represents one complete rotation about the origin

so 25π/6 = π/6

so sec( 25π/6) =sec(π/6)=2/$\sqrt{3}$.

tan 6π

=tan(6π+0)

=0.