Find the value of 1-tan 2 15 / 1+tan 2 15
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"1-tan215°/1+tan215°
= (Tan45°-Tan215°)/(1+Tan45°Tan215°)
= Tan (45°-215°)
= Tan (-170°)
=-Tan170°
Or
2 Tan15°/(1-Tan^2 15°)
There are trig identity for double angle of tangent: Tan (2A) = 2tanA / (1 - tan²A)
Let A = 15°:
Tan (2∙15°) = 2tan15° / (1 - tan²15°)
Tan 30° = 2tan15° / (1 - tan²15°)
√3/3 = 2tan15° / (1 - tan²15°)
"
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