Question

find the value of 1-tan square 45 degree/1+tansquare 45 degree

Answer 1

=1-tan square 45 degree/1+tan square 45
=1-1square/1+1square
=1-1/1+1
=0/2
=0 [tan45=1]




hope it helps you

Answer 2

Answer:

Value of $\frac{1-tan^{2}45}{1+tan^{2}45}$=$0$

Step-by-step explanation:

Value of $\frac{1-tan^{2}45}{1+tan^{2}45}$

= $\frac{1-1^{2}}{1+1^{2}}$

/*Since , tan45° = 1 */

= $\frac{1-1}{1+1}$

= $\frac{0}{2}$

= $0$

Therefore,

Value of $\frac{1-tan^{2}45}{1+tan^{2}45}$ = $0$

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