find the value of 1 + tan
square upon 1 + cot square
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1+tan©\1+cot©= 1+sin©\cos©//1+cos ©\sin©= sin ©+cos ©\cos©/sin ©+cos©\sin©=. sin©(sin©+cos©)/cos©(sin ©+cos©)=. sin©\cos©=tan©. hence tan© answer hoga thanks
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