Question

find the value of
(1+tan²) (1-sin) (1+sin)

Answer 1

[ 1+ tan^2 theta] [ 1 + sin theta ] [ 1- sin theta ]
= sec^2 theta * [ 1 - sin^2 theta ]
= sec^2 theta * cos^2theta
= 1 / cos^2theta * cos^2 theta
= 1.

Answer 2

 = (1+tan^2A)(1-sinA)(1+sinA)
 = (1+tan^2A)(1-sin^A)
 = (sec^2A)(cos^2A)
 = sec^2A * 1/sec^2A
 =1